Pengumuman mengenai cEh akan dipaparkan di sini dalam beberapa hari akan datang. Sila tunggu.
Two days have passed, thank you all for your understanding and anticipation.
Before we begin to consider the rectilinear motion of a massive particle (and gravity too, but not now) in a metric signature with (+,+,+,+,+), what is necessary to do? We need to know that: in cEh the spacetime interval of special relativity (Thales’s theorem) is replaced on the Pythagorean theorem, in which the square of the hypotenuse (ct) is equal to the sum of the squares of the other two. The sides (legs) are space and time. The motion of spacetime, defined as a change in the corresponding coordinate, occurs along the spatial axis oX with velocity v and along the time axis ot with velocity c. Let’s write this as the Pythagorean theorem..
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For the oY and oZ axes, the velocity v is zero, yielding the identity (ct)^2≡(ct)^2. Before moving on to the oX axis, what is necessary to do? We need to define t as the transition time of a massive particle from a previous state of the our universe to its next. To obtain equality for the x-axis, we need to change the formula:
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Note that (c^2 – v^2) is c^2 reduced by the gamma factor (or also the Lorentz factor) squared, which yields
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It’s time to return to physics. This may come as a surprise, but over more than a century, knowledge in physics has only increased, formalizing the sciences of astrophysics and cosmology. Let’s start with quantum physics and the gamma factor. What does the motion of a massive particle represent from a physical perspective? In the most common and simplest version, the motion of a massive particle along the x-axis with a velocity v of cEh means an increase in its total energy and a decrease in time by a factor of the Lorentz factor. That is, the magnitude of the quantum spin remains unchanged, which corresponds to quantum physics and, of course, to reality. Motion along the x-axis with a velocity v also means a decrease in the length of this massive particle by a factor of the Lorentz factor. Why should the length of this massive particle decrease by a factor of the Lorentz factor? Therefore, defining the velocity v as displacement by a fixed fraction of the Planck length in one Planck time, we must recognize that the longitudinal dimension decreases proportionally to the decrease in the temporal dimension – by the same factor of the gamma factor (otherwise, the particle’s energy would change, which cannot occur in uniform rectilinear motion). In the final formula, t remains unchanged. This means that during the particle’s transition from the previous state of the our universe to its next, the massive particle traveled a gamma of short segments. What happens to each of these segments of space after the massive particle traverses them? Nothing special happens; these short segments are successively lengthened again to their normal, uncompressed state.
REM: In our Universe, where each particle has only positive energy and strictly non-negative quantum spin, the maximum possible speed of travel is equal to the fundamental velocity, the speed of light in a vacuum. And the distance traveled in space by such (massless) particles during a time t will be equal to ct. Let’s imagine that, using a sufficientlycompact LINear ACcelerator, we managed to accelerate electrons with non-zero mass to a gamma factor of 10, which corresponds to a speed of 0.995 times the speed of light in a vacuum. Over the same time t, the distance of travel in space will be 0.995⋅ct, that is, less than 1.000⋅ct for massless particles. There’s a slight complication here. It’s that 0.995⋅ct is not a distance in ordinary space, but in compressed space, which becomes ordinary after the electron’s passage. And the length of this space, measured immediately after the end of time t, will be equal to 9.95⋅ct. Observationally, this will resemble superluminal travel, which is not actually superluminal. Are there observations of anything resembling superluminal travel of radiating matter? Yes, there are observations of superluminal jets in some BL Lac objects, blazars, quasars and microquasars, and radio galaxies. Is there a practical use for such quasi-superluminal travel? No, there is no such use on Earth… or there is, but I don’t know about it. A little about practical benefits: even using a fairly compact LINear ACcelerator with a gamma factor of 10 for electrons on a spacecraft, coupled with a transceiver, can reduce the ping time when communicating with an orbital station by the same factor of ten… which is quite acceptable for distances of several astronomical units. Communication between receivers and transmitters over distances of several parsecs or more will require a gamma factor of 1000 or more, which will require more technically sophisticated transceivers. Yes, it’s difficult, but a ping time between star systems of a few hours or less will prevent humanity from disintegrating into numerous separate, informationally isolated civilizations.